What is x^2+y^2-2x+4y=4 ?

The solution to x^2+y^2-2x+4y=4 is Circle with (a,b)=(1,-2),r=3

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x^2+y^2-2x+4y=4

x^{2} + y^{2} - 2 x + 4 y = 4

(a, b) = (1, - 2), r = 3

Solution steps

x^{2} + y^{2} - 2 x + 4 y = 4

Rewrite

x^{2} + y^{2} - 2 x + 4 y = 4

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 3

(x - 3)^{2} + (y - 4)^{2} = 16

(x + 5)^{2} + (y + 6)^{2} = \frac{2}{3}

x^{2} + y^{2} = 36 - 3 x^{2} - 3 y^{2}

p^{2} + q^{2} = 16

(x - 4)^{2} + (y - 3)^{2} = 1

What is x^2+y^2-2x+4y=4 ?
The solution to x^2+y^2-2x+4y=4 is Circle with (a,b)=(1,-2),r=3