What is 2x^2+2y^2-20x+8y+34=0 ?

The solution to 2x^2+2y^2-20x+8y+34=0 is Circle with (a,b)=(5,-2),r=2sqrt(3)

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2x^2+2y^2-20x+8y+34=0

2 x^{2} + 2 y^{2} - 20 x + 8 y + 34 = 0

(a, b) = (5, - 2), r = 23

Solution steps

2 x^{2} + 2 y^{2} - 20 x + 8 y + 34 = 0

Rewrite

2 x^{2} + 2 y^{2} - 20 x + 8 y + 34 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 23

3 x^{2} + 3 y^{2} - 12 x + 15 y = 21

(x - 4)^{2} + (y - 1)^{2} = 49

x^{2} + y^{2} - 32 x - 8 y + 264 = 0

(x - 2)^{2} + (y + 5)^{2} = 49

\frac{( x + 5 ) ^{2}}{\frac{9}{25}} + \frac{( y + 4 ) ^{2}}{\frac{9}{25}} = 1

What is 2x^2+2y^2-20x+8y+34=0 ?
The solution to 2x^2+2y^2-20x+8y+34=0 is Circle with (a,b)=(5,-2),r=2sqrt(3)