What is x^2-8x+y^2+12y=-43 ?

The solution to x^2-8x+y^2+12y=-43 is Circle with (a,b)=(4,-6),r=3

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x^2-8x+y^2+12y=-43

x^{2} - 8 x + y^{2} + 12 y = - 43

(a, b) = (4, - 6), r = 3

Solution steps

x^{2} - 8 x + y^{2} + 12 y = - 43

Rewrite

x^{2} - 8 x + y^{2} + 12 y = - 43

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 6))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (4, - 6), r = 3

x^{2} + y^{2} - 10 x + 26 y + 167 = 0

(x + 4)^{2} + (y + 1)^{2} = 9

x^{2} + 2 x + 1 + y^{2} - 8 y + 16 = - 16 + 1 + 16

3 x^{2} + 3 y^{2} - 3 x - 3 y - 9 = 0

(x - 6)^{2} + (y + 2)^{2} = 16

What is x^2-8x+y^2+12y=-43 ?
The solution to x^2-8x+y^2+12y=-43 is Circle with (a,b)=(4,-6),r=3