What is (x-(-1))^2+(y-1)^2=sqrt(6)^2 ?

The solution to (x-(-1))^2+(y-1)^2=sqrt(6)^2 is Circle with (a,b)=(-1,1),r=sqrt((\sqrt{6))^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-(-1))^2+(y-1)^2=sqrt(6)^2

(x - (- 1))^{2} + (y - 1)^{2} = 6^{2}

(a, b) = (- 1, 1), r = (6)^{2}

Solution steps

(x - (- 1))^{2} + (y - 1)^{2} = (6)^{2}

Rewrite

(x - (- 1))^{2} + (y - 1)^{2} = 6^{2}

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = ((6)^{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = (6)^{2}

2 x^{2} + 2 y^{2} - 2 = 0

(x + 7)^{2} + (y - 2)^{2} = 25

(x - \frac{5}{4})^{2} + (y + \frac{9}{2})^{2} = 14

x^{2} - 8 x + y^{2} = 0

x^{2} + y^{2} - 8 y + 12 = 0

What is (x-(-1))^2+(y-1)^2=sqrt(6)^2 ?
The solution to (x-(-1))^2+(y-1)^2=sqrt(6)^2 is Circle with (a,b)=(-1,1),r=sqrt((\sqrt{6))^2}