What is ((x-19)/4)^2+((y-9)/4)^2=17 ?

The solution to ((x-19)/4)^2+((y-9)/4)^2=17 is Circle with (a,b)=(19,9),r=4sqrt(17)

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((x-19)/4)^2+((y-9)/4)^2=17

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

(a, b) = (19, 9), r = 417

Solution steps

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

Rewrite

(\frac{x - 19}{4})^{2} + (\frac{y - 9}{4})^{2} = 17

in the form of the standard circle equation

(x - 19)^{2} + (y - 9)^{2} = (417)^{2}

Therefore the circle properties are:

(a, b) = (19, 9), r = 417

x^{2} + y^{2} + 4 x - 8 y + 16 = 0

2 x^{2} + 4 x + 2 y^{2} = 0

(x - 7)^{2} + (y + 1)^{2} = 36

x^{2} + 16 x + y^{2} - 12 y = 0

x^{2} + (y - 1)^{2} = 64

What is ((x-19)/4)^2+((y-9)/4)^2=17 ?
The solution to ((x-19)/4)^2+((y-9)/4)^2=17 is Circle with (a,b)=(19,9),r=4sqrt(17)