What is x^2+(y-1)^2=64 ?

The solution to x^2+(y-1)^2=64 is Circle with (a,b)=(0,1),r=8

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x^2+(y-1)^2=64

x^{2} + (y - 1)^{2} = 64

(a, b) = (0, 1), r = 8

Solution steps

x^{2} + (y - 1)^{2} = 64

Rewrite

x^{2} + (y - 1)^{2} = 64

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 8

x^{2} + y^{2} + 8 x - 6 y + 10 = 0

x^{2} + y^{2} - 14 x + 12 y - 36 = 0

x^{2} + y^{2} + 6 x - 10 y + 17 = 0

(x - 6)^{2} + (y - 8)^{2} = 1 0^{2}

x^{2} + y^{2} + \frac{4 ( x ^{2} + y ^{2} )}{21} = 25

What is x^2+(y-1)^2=64 ?
The solution to x^2+(y-1)^2=64 is Circle with (a,b)=(0,1),r=8