What is 14y+y^2+x^2=12x-18 ?

The solution to 14y+y^2+x^2=12x-18 is Circle with (a,b)=(6,-7),r=sqrt(67)

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14y+y^2+x^2=12x-18

14 y + y^{2} + x^{2} = 12 x - 18

(a, b) = (6, - 7), r = 67

Solution steps

14 y + y^{2} + x^{2} = 12 x - 18

Rewrite

14 y + y^{2} + x^{2} = 12 x - 18

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 7))^{2} = (67)^{2}

Therefore the circle properties are:

(a, b) = (6, - 7), r = 67

(x + 2)^{2} + (y - 3)^{2} = 40

(x + 2)^{2} + (y - 3)^{2} = 20

(x + 1)^{2} + (y + 6)^{2} = 8^{2}

(x + 2)^{2} + (y - 3)^{2} = 10

(x - 7)^{(2)} + (y - 7)^{(2)} = \frac{( 4 )}{( 9 )}

What is 14y+y^2+x^2=12x-18 ?
The solution to 14y+y^2+x^2=12x-18 is Circle with (a,b)=(6,-7),r=sqrt(67)