What is 3x^2+6x+9+3y^2-18y+81=108 ?

The solution to 3x^2+6x+9+3y^2-18y+81=108 is Circle with (a,b)=(-1,3),r=4

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3x^2+6x+9+3y^2-18y+81=108

3 x^{2} + 6 x + 9 + 3 y^{2} - 18 y + 81 = 108

(a, b) = (- 1, 3), r = 4

Solution steps

3 x^{2} + 6 x + 9 + 3 y^{2} - 18 y + 81 = 108

Rewrite

3 x^{2} + 6 x + 9 + 3 y^{2} - 18 y + 81 = 108

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 3)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 1, 3), r = 4

2 y = y^{2} + (x + 4)^{2}

x^{2} + (y - 7)^{2} = 9

x^{2} + (y - 7)^{2} = 5

x^{2} + (y - 7)^{2} = 1

(x - 3)^{2} + (y - 5)^{2} = 9

What is 3x^2+6x+9+3y^2-18y+81=108 ?
The solution to 3x^2+6x+9+3y^2-18y+81=108 is Circle with (a,b)=(-1,3),r=4