What is x^2+y^2-4x-11y+21=0 ?

The solution to x^2+y^2-4x-11y+21=0 is Circle with (a,b)=(2, 11/2),r=(sqrt(53))/2

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x^2+y^2-4x-11y+21=0

x^{2} + y^{2} - 4 x - 11 y + 21 = 0

(a, b) = (2, \frac{11}{2}), r = \frac{53}{2}

Solution steps

x^{2} + y^{2} - 4 x - 11 y + 21 = 0

Rewrite

x^{2} + y^{2} - 4 x - 11 y + 21 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - \frac{11}{2})^{2} = (\frac{53}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, \frac{11}{2}), r = \frac{53}{2}

(x - 0)^{2} + (y - 0)^{2} = 10

9 x^{2} + 9 y^{2} - 6 x - 24 y = 19

x^{2} + y^{2} + 6 x + 8 y = 9

x^{(2)} + y^{(2)} + 4 x - 6 y - 12 = 0

x, x^{2} + Y (x)^{2} = 4

What is x^2+y^2-4x-11y+21=0 ?
The solution to x^2+y^2-4x-11y+21=0 is Circle with (a,b)=(2, 11/2),r=(sqrt(53))/2