What is (x+0)^2+(y+0)^2=6 ?

The solution to (x+0)^2+(y+0)^2=6 is Circle with (a,b)=(0,0),r=sqrt(6)

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(x+0)^2+(y+0)^2=6

(x + 0)^{2} + (y + 0)^{2} = 6

(a, b) = (0, 0), r = 6

Solution steps

(x + 0)^{2} + (y + 0)^{2} = 6

Rewrite

(x + 0)^{2} + (y + 0)^{2} = 6

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

(x + 2)^{2} + (y - 2)^{2} = 16

(x + 5)^{2} + (y - 2)^{2} = 61

(x + 2)^{2} + (y + \frac{1}{2})^{2} = \frac{17}{4}

(2 x^{2} - 12 x) + (2 y^{2} + 8 y) = 24

2 x^{2} + 2 y^{2} + 4 x - 8 y - 8 = 0

What is (x+0)^2+(y+0)^2=6 ?
The solution to (x+0)^2+(y+0)^2=6 is Circle with (a,b)=(0,0),r=sqrt(6)