What is (x-4)^2+(y+10)^2=81 ?

The solution to (x-4)^2+(y+10)^2=81 is Circle with (a,b)=(4,-10),r=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-4)^2+(y+10)^2=81

(x - 4)^{2} + (y + 10)^{2} = 81

(a, b) = (4, - 10), r = 9

Solution steps

(x - 4)^{2} + (y + 10)^{2} = 81

Rewrite

(x - 4)^{2} + (y + 10)^{2} = 81

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 10))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (4, - 10), r = 9

x^{2} + y^{2} + 14 x - 10 y + 65 = 0 x

3 x^{2} + 3 y^{2} - 30 x - 6 y + 75 = 0

0.2 x^{2} + x + 0.2 y^{2} - 4 y = 1

x^{2} + y^{2} - 5 x = 20 - 2 y

(x^{2} + 14 x 9) + (y^{2} + 12 y + 36) = 36 + 49 + 36

What is (x-4)^2+(y+10)^2=81 ?
The solution to (x-4)^2+(y+10)^2=81 is Circle with (a,b)=(4,-10),r=9