What is x^2-x+y^2+9y+11=0 ?

The solution to x^2-x+y^2+9y+11=0 is Circle with (a,b)=(1/2 ,-9/2),r=sqrt(19/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-x+y^2+9y+11=0

x^{2} - x + y^{2} + 9 y + 11 = 0

(a, b) = (\frac{1}{2}, - \frac{9}{2}), r = \frac{19}{2}

Solution steps

x^{2} - x + y^{2} + 9 y + 11 = 0

Rewrite

x^{2} - x + y^{2} + 9 y + 11 = 0

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - (- \frac{9}{2}))^{2} = (\frac{19}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{9}{2}), r = \frac{19}{2}

(x + 7)^{2} + (y - 4)^{2} = 50

(x - 4)^{2} + (y - 7)^{2} = 100

x^{2} + y^{2} = - 8 x - 43 - 12 y

(x - 1)^{2} + (y + 3)^{2} = 3

x^{2} + y^{2} - 5 x + 4 y = 16

What is x^2-x+y^2+9y+11=0 ?
The solution to x^2-x+y^2+9y+11=0 is Circle with (a,b)=(1/2 ,-9/2),r=sqrt(19/2)