What is ((x-5)^2}{3^2}+\frac{(y+5)^2)/9 =1 ?

The solution to ((x-5)^2}{3^2}+\frac{(y+5)^2)/9 =1 is Circle with (a,b)=(5,-5),r=3

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((x-5)^2}{3^2}+\frac{(y+5)^2)/9 =1

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

(a, b) = (5, - 5), r = 3

Solution steps

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, - 5), r = 3

x^{2} - 2 x + y^{2} + 4 y = 31

x^{2} + y^{2} - 4 x + 2 y + 2 = 0

x^{2} + y^{2} + 6 y + 3 = 0

x^{2} + y^{2} + x - \frac{1}{2} y = 0

(x - 0)^{2} + (y - 15)^{2} = 9

What is ((x-5)^2}{3^2}+\frac{(y+5)^2)/9 =1 ?
The solution to ((x-5)^2}{3^2}+\frac{(y+5)^2)/9 =1 is Circle with (a,b)=(5,-5),r=3