What is x^2-10x+25+y^2+6y+9=4 ?

The solution to x^2-10x+25+y^2+6y+9=4 is Circle with (a,b)=(5,-3),r=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2-10x+25+y^2+6y+9=4

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

(a, b) = (5, - 3), r = 2

Solution steps

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

Rewrite

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 3))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (5, - 3), r = 2

(y + 5)^{2} = 100 - (x + 2)^{2}

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

x^{2} - 2 y + y^{2} = 12

8 = x^{2} + y^{2}

What is x^2-10x+25+y^2+6y+9=4 ?
The solution to x^2-10x+25+y^2+6y+9=4 is Circle with (a,b)=(5,-3),r=2