What is (x-5)^2+(y+2)^2=58 ?

The solution to (x-5)^2+(y+2)^2=58 is Circle with (a,b)=(5,-2),r=sqrt(58)

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(x-5)^2+(y+2)^2=58

(x - 5)^{2} + (y + 2)^{2} = 58

(a, b) = (5, - 2), r = 58

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 58

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 58

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = (58)^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 58

3 x^{2} + 3 y^{2} + 2 x - 4 y = - \frac{1}{2}

x^{2} - 5 = - y^{2}

(x - 5)^{2} + (y + 2)^{2} = 64

9 (\frac{x - 3}{9})^{2} + 9 (\frac{y + 12}{9})^{2} = 172

(x - 1.5)^{2} + (y + 2.5)^{2} = 1.15

What is (x-5)^2+(y+2)^2=58 ?
The solution to (x-5)^2+(y+2)^2=58 is Circle with (a,b)=(5,-2),r=sqrt(58)