What is x^2+(y+1/2)^2= 1/4 ?

The solution to x^2+(y+1/2)^2= 1/4 is Circle with (a,b)=(0,-1/2),r= 1/2

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x^2+(y+1/2)^2= 1/4

x^{2} + (y + \frac{1}{2})^{2} = \frac{1}{4}

(a, b) = (0, - \frac{1}{2}), r = \frac{1}{2}

Solution steps

x^{2} + (y + \frac{1}{2})^{2} = \frac{1}{4}

Rewrite

x^{2} + (y + \frac{1}{2})^{2} = \frac{1}{4}

in the form of the standard circle equation

(x - 0)^{2} + (y - (- \frac{1}{2}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, - \frac{1}{2}), r = \frac{1}{2}

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

x^{2} + y^{2} + 6 x - 22 y + 66 = 0

x^{2} + y^{2} - 12 x + 24 y + 116 = 0

a^{2} = 5 - b^{2}

x^{2} + y^{2} - 2 \cdot x - 5.4 \cdot y + 7.29 = 0

What is x^2+(y+1/2)^2= 1/4 ?
The solution to x^2+(y+1/2)^2= 1/4 is Circle with (a,b)=(0,-1/2),r= 1/2