What is x^2+y^2-2x-8y=0 ?

The solution to x^2+y^2-2x-8y=0 is Circle with (a,b)=(1,4),r=sqrt(17)

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x^2+y^2-2x-8y=0

x^{2} + y^{2} - 2 x - 8 y = 0

(a, b) = (1, 4), r = 17

Solution steps

x^{2} + y^{2} - 2 x - 8 y = 0

Rewrite

x^{2} + y^{2} - 2 x - 8 y = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 17

x^{(2)} + y^{(2)} - 6 x - 4 y - 9 = 0

\frac{8 x ^{2} - 12 x + 8 y ^{2} + 20 y + 17}{8} = 2

(x + 1)^{2} + (y - 4)^{2} = 16

x^{2} + (y - 3)^{2} = 100

(x - 15)^{2} + (y + 15)^{2} = 256

What is x^2+y^2-2x-8y=0 ?
The solution to x^2+y^2-2x-8y=0 is Circle with (a,b)=(1,4),r=sqrt(17)