What is (x-3)^2+(y-7)^2=52 ?

The solution to (x-3)^2+(y-7)^2=52 is Circle with (a,b)=(3,7),r=sqrt(52)

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(x-3)^2+(y-7)^2=52

(x - 3)^{2} + (y - 7)^{2} = 52

(a, b) = (3, 7), r = 52

Solution steps

(x - 3)^{2} + (y - 7)^{2} = 52

Rewrite

(x - 3)^{2} + (y - 7)^{2} = 52

in the form of the standard circle equation

(x - 3)^{2} + (y - 7)^{2} = (52)^{2}

Therefore the circle properties are:

(a, b) = (3, 7), r = 52

4 x^{2} - 20 x + 4 y^{2} - 8 y = 7

36 x^{2} + 36 y^{2} - 48 x + 36 y - 119 = 0

x^{2} + y^{2} - 9 x + 4 y - 117 = 0

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

x^{2} + y^{2} + 12 x - 16 y = 0

What is (x-3)^2+(y-7)^2=52 ?
The solution to (x-3)^2+(y-7)^2=52 is Circle with (a,b)=(3,7),r=sqrt(52)