What is y^2+x^2-16x+16y+92=0 ?

The solution to y^2+x^2-16x+16y+92=0 is Circle with (a,b)=(8,-8),r=6

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y^2+x^2-16x+16y+92=0

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

(a, b) = (8, - 8), r = 6

Solution steps

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

Rewrite

y^{2} + x^{2} - 16 x + 16 y + 92 = 0

in the form of the standard circle equation

(x - 8)^{2} + (y - (- 8))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (8, - 8), r = 6

x^{2} + y^{2} + 12 x - 16 y = 0

a^{2} + b^{2} = 6

(x - 1)^{2} + (y - 5)^{2} = 81

x^{2} + (y - 22.5)^{2} = 22. 5^{2}

x^{2} + y^{2} - 6 x - 8 y - 44 = 0

What is y^2+x^2-16x+16y+92=0 ?
The solution to y^2+x^2-16x+16y+92=0 is Circle with (a,b)=(8,-8),r=6