What is 3=3x^2+3y^2 ?

The solution to 3=3x^2+3y^2 is Circle with (a,b)=(0,0),r=1

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3=3x^2+3y^2

3 = 3 x^{2} + 3 y^{2}

(a, b) = (0, 0), r = 1

Solution steps

3 = 3 x^{2} + 3 y^{2}

Rewrite

3 = 3 x^{2} + 3 y^{2}

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

x^{2} - 8 x + y^{2} - 6 y + 25 = 1

x^{2} + y^{2} + 6 x - 2 x - 2 y + 1 = 0

x^{2} + y^{2} - 6 x - 2 y = 15

x^{2} + 2 x + y^{2} - 6 y = 15

16 x^{2} + 80 x + 16 y^{2} - 112 y = - 247

What is 3=3x^2+3y^2 ?
The solution to 3=3x^2+3y^2 is Circle with (a,b)=(0,0),r=1