What is x^2+y^2-3x-6y+9=0 ?

The solution to x^2+y^2-3x-6y+9=0 is Circle with (a,b)=(3/2 ,3),r= 3/2

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x^2+y^2-3x-6y+9=0

x^{2} + y^{2} - 3 x - 6 y + 9 = 0

(a, b) = (\frac{3}{2}, 3), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} - 3 x - 6 y + 9 = 0

Rewrite

x^{2} + y^{2} - 3 x - 6 y + 9 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 3)^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 3), r = \frac{3}{2}

4 x^{(2)} + 4 y^{(2)} - 56 x + 8 y + 56 = 0

100 - 25 x^{2} - 25 y^{2} = 0

(x + 8)^{2} + (y + 2)^{2} = 36

x^{2} - 2 x + y^{2} - 8 = 0

x^{2} - 14 x + y^{2} + 2 y + 50 = 4

What is x^2+y^2-3x-6y+9=0 ?
The solution to x^2+y^2-3x-6y+9=0 is Circle with (a,b)=(3/2 ,3),r= 3/2