What is x^2-14x+y^2+12y=36 ?

The solution to x^2-14x+y^2+12y=36 is Circle with (a,b)=(7,-6),r=11

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x^2-14x+y^2+12y=36

x^{2} - 14 x + y^{2} + 12 y = 36

(a, b) = (7, - 6), r = 11

Solution steps

x^{2} - 14 x + y^{2} + 12 y = 36

Rewrite

x^{2} - 14 x + y^{2} + 12 y = 36

in the form of the standard circle equation

(x - 7)^{2} + (y - (- 6))^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (7, - 6), r = 11

x^{2} + y^{2} - 8 x - 12 y + 48 = 0

9 - x^{2} - y^{2} > 0

x^{2} + x + y^{2} + 11 y - 32 = 0

x^{2} + y^{2} + 6 x - 8 y = - 9

x^{2} + 8 x + y^{2} - 4 y - 29 = 0

What is x^2-14x+y^2+12y=36 ?
The solution to x^2-14x+y^2+12y=36 is Circle with (a,b)=(7,-6),r=11