What is x^2+x+y^2+11y-32=0 ?

The solution to x^2+x+y^2+11y-32=0 is Circle with (a,b)=(-1/2 ,-11/2),r=(5sqrt(5))/(sqrt(2))

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x^2+x+y^2+11y-32=0

x^{2} + x + y^{2} + 11 y - 32 = 0

(a, b) = (- \frac{1}{2}, - \frac{11}{2}), r = \frac{5 5}{2}

Solution steps

x^{2} + x + y^{2} + 11 y - 32 = 0

Rewrite

x^{2} + x + y^{2} + 11 y - 32 = 0

in the form of the standard circle equation

(x - (- \frac{1}{2}))^{2} + (y - (- \frac{11}{2}))^{2} = (\frac{5 5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{1}{2}, - \frac{11}{2}), r = \frac{5 5}{2}

x^{2} + y^{2} + 6 x - 8 y = - 9

x^{2} + 8 x + y^{2} - 4 y - 29 = 0

x^{2} + y^{2} - 2 x + 6 y - 10 = 0

3 x^{2} + 18 x + 3 y^{2} - 6 y = 18

4 x + 2 y = x^{2} + y^{2}

What is x^2+x+y^2+11y-32=0 ?
The solution to x^2+x+y^2+11y-32=0 is Circle with (a,b)=(-1/2 ,-11/2),r=(5sqrt(5))/(sqrt(2))