What is (x+5)^2+(y-1)^2=7 ?

The solution to (x+5)^2+(y-1)^2=7 is Circle with (a,b)=(-5,1),r=sqrt(7)

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(x+5)^2+(y-1)^2=7

(x + 5)^{2} + (y - 1)^{2} = 7

(a, b) = (- 5, 1), r = 7

Solution steps

(x + 5)^{2} + (y - 1)^{2} = 7

Rewrite

(x + 5)^{2} + (y - 1)^{2} = 7

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 1)^{2} = (7)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 1), r = 7

(x - (- 2))^{2} + (y - 1)^{2} = 5^{2}

(x - 3)^{2} + (y + 13)^{2} = 9

x^{2} + y^{2} - 4 x + 2 y - 2 = 0

x^{2} + y^{2} + 9 x + 10 = 0

4 y^{2} - 72 y = 316 - 4 x^{2} - 24 x

What is (x+5)^2+(y-1)^2=7 ?
The solution to (x+5)^2+(y-1)^2=7 is Circle with (a,b)=(-5,1),r=sqrt(7)