What is 0=3-6(x^2+y^2) ?

The solution to 0=3-6(x^2+y^2) is Circle with (a,b)=(0,0),r=sqrt(1/2)

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0=3-6(x^2+y^2)

0 = 3 - 6 (x^{2} + y^{2})

(a, b) = (0, 0), r = \frac{1}{2}

Solution steps

0 = 3 - 6 (x^{2} + y^{2})

Rewrite

0 = 3 - 6 (x^{2} + y^{2})

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{1}{2}

x^{2} + y^{2} + (- x^{2} + y^{2})^{2} = 9

(x - 3)^{2} + (y + 5)^{2} = 100

π x^{(2)} + π y^{(2)} + 8 x - 10 π y - 400 = 0

x^{2} + y^{2} + 14 x + 8 y + 3 = 0

x^{2} + y^{2} + 18 x - 30 y + 297 = 0

What is 0=3-6(x^2+y^2) ?
The solution to 0=3-6(x^2+y^2) is Circle with (a,b)=(0,0),r=sqrt(1/2)