What is x^2+y^2+6x+10y+9=0 ?

The solution to x^2+y^2+6x+10y+9=0 is Circle with (a,b)=(-3,-5),r=5

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x^2+y^2+6x+10y+9=0

x^{2} + y^{2} + 6 x + 10 y + 9 = 0

(a, b) = (- 3, - 5), r = 5

Solution steps

x^{2} + y^{2} + 6 x + 10 y + 9 = 0

Rewrite

x^{2} + y^{2} + 6 x + 10 y + 9 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - (- 5))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, - 5), r = 5

x^{2} + y^{2} - \frac{2}{3} x + \frac{8}{3} y = \frac{19}{9}

x^{2} + 14 x + y^{2} - 2 y - 50 = 0

(x - 2)^{2} + (y - 1.5)^{2} = 9

x^{2} + y^{2} + 2 x + 4 y - 31 = 0

x^{2} + y^{2} + 10 x - 2 y - 23 = 0

What is x^2+y^2+6x+10y+9=0 ?
The solution to x^2+y^2+6x+10y+9=0 is Circle with (a,b)=(-3,-5),r=5