What is (x-10)^2+(y-6)^2=1 ?

The solution to (x-10)^2+(y-6)^2=1 is Circle with (a,b)=(10,6),r=1

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(x-10)^2+(y-6)^2=1

(x - 10)^{2} + (y - 6)^{2} = 1

(a, b) = (10, 6), r = 1

Solution steps

(x - 10)^{2} + (y - 6)^{2} = 1

Rewrite

(x - 10)^{2} + (y - 6)^{2} = 1

in the form of the standard circle equation

(x - 10)^{2} + (y - 6)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (10, 6), r = 1

x^{2} + y^{2} - 18 x + 16 y + 81 = 0

(x + 2)^{2} + y^{2} = 8 y - 7

4 x^{2} + 4 y^{2} + 24 x - 8 y - 41 = 0

x^{2} + y^{2} - 6 x - 12 y + 36 = 0

2 x^{2} + 2 y^{2} + 15 x + 15 y - 15 = 0

What is (x-10)^2+(y-6)^2=1 ?
The solution to (x-10)^2+(y-6)^2=1 is Circle with (a,b)=(10,6),r=1