What is (x-5)^2+(y+2)^2=3 ?

The solution to (x-5)^2+(y+2)^2=3 is Circle with (a,b)=(5,-2),r=sqrt(3)

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(x-5)^2+(y+2)^2=3

(x - 5)^{2} + (y + 2)^{2} = 3

(a, b) = (5, - 2), r = 3

Solution steps

(x - 5)^{2} + (y + 2)^{2} = 3

Rewrite

(x - 5)^{2} + (y + 2)^{2} = 3

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 2))^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (5, - 2), r = 3

(x - 5)^{2} + (y + 2)^{2} = 4

(x + \frac{10}{3})^{2} + y^{2} = 4

x^{2} + y^{2} + 5 x - 7 y - 18 = 0

x^{2} + (y - 10)^{2} = 225

2 x^{2} - 6 x + 2 y^{2} + 2 y - 45 = 0

What is (x-5)^2+(y+2)^2=3 ?
The solution to (x-5)^2+(y+2)^2=3 is Circle with (a,b)=(5,-2),r=sqrt(3)