Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center 4x^2+4y^2-16=0center center x^2+y^2+12y+32=0center center x^2-6x+y^2=7center center (x-3)^2+y^2=36center center 4x^2+4y^2-12x+24y+9=0center

Frequently Asked Questions (FAQ)

  • What is the center x^2+(y-3)^2=16 ?

    The center x^2+(y-3)^2=16 is (0,3)