What is the center 4x^2+4y^2-12x+24y+9=0 ?

The center 4x^2+4y^2-12x+24y+9=0 is (3/2 ,-3)

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center 4x^2+4y^2-12x+24y+9=0

center

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

(\frac{3}{2}, - 3)

Solution steps

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

Rewrite

4 x^{2} + 4 y^{2} - 12 x + 24 y + 9 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 3))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 3), r = 3

And the center is:

(\frac{3}{2}, - 3)

x^{2} + y^{2} - 8 x - 3 = 0

4 x^{2} + 4 y^{2} = 100

(x - 2)^{2} + (y + 1)^{2} = 9

x^{2} + y^{2} - 2 x - 8 y - 19 = 0

x^{2} + y^{2} + 2 x - 4 y - 15 = 0

What is the center 4x^2+4y^2-12x+24y+9=0 ?
The center 4x^2+4y^2-12x+24y+9=0 is (3/2 ,-3)