Solution

center

Solution

Solution steps
Rewrite in the form of the standard circle equation
Therefore the circle properties are:
And the center is:

Popular Examples

center (x-5)^2+(y-3)^2=49center center y^2+x^2+24x+10y+160=0center center (x+2)^2+(y+3)^2=9center center (x+2)^2+(y-5)^2=4center center y^2+4x-20-2y=-x^2center

Frequently Asked Questions (FAQ)

  • What is the center x^2+y^2-12x+8y-5=0 ?

    The center x^2+y^2-12x+8y-5=0 is (6,-4)