What is the center x^2+y^2-20x-18y+144=0 ?

The center x^2+y^2-20x-18y+144=0 is (10,9)

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center x^2+y^2-20x-18y+144=0

center

x^{2} + y^{2} - 20 x - 18 y + 144 = 0

(10, 9)

Solution steps

x^{2} + y^{2} - 20 x - 18 y + 144 = 0

Rewrite

x^{2} + y^{2} - 20 x - 18 y + 144 = 0

in the form of the standard circle equation

(x - 10)^{2} + (y - 9)^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (10, 9), r = 37

And the center is:

(10, 9)

5 x^{2} + 40 x + 5 y^{2} = 0

x^{2} + y^{2} - 6 = 0

(x - 17)^{2} + (y + 5)^{2} = 144

(x + 5)^{2} + (y + 5)^{2} = 64

2 x^{2} + 2 y^{2} - 4 x + 12 y - 18 = 0

What is the center x^2+y^2-20x-18y+144=0 ?
The center x^2+y^2-20x-18y+144=0 is (10,9)