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Popular >

radius x^2+y^2-4x=0

Solution

radius

x^{2} + y^{2} - 4 x = 0

Solution

r = 2

Solution steps

x^{2} + y^{2} - 4 x = 0

Rewrite

x^{2} + y^{2} - 4 x = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, 0), r = 2

And the radius is:

r = 2

Popular Examples

radius 2x^2+2y^2-12x+8y-24=0 radius

2 x^{2} + 2 y^{2} - 12 x + 8 y - 24 = 0

radius x^2+y^2-5x+4y=46 radius

x^{2} + y^{2} - 5 x + 4 y = 46

radius x^2+y^2=16 radius

x^{2} + y^{2} = 16

radius x^2+y^2=49 radius

x^{2} + y^{2} = 49

radius (x-6)^2+(y-4)^2-64=0 radius

(x - 6)^{2} + (y - 4)^{2} - 64 = 0

Frequently Asked Questions (FAQ)

What is the radius x^2+y^2-4x=0 ?
The radius x^2+y^2-4x=0 is r=2