What is the radius 5x^2-20x+5y^2+30y-11=0 ?

The radius 5x^2-20x+5y^2+30y-11=0 is r=(2sqrt(19))/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius 5x^2-20x+5y^2+30y-11=0

radius

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

r = \frac{2 19}{5}

Solution steps

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

Rewrite

5 x^{2} - 20 x + 5 y^{2} + 30 y - 11 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (\frac{2 19}{5})^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = \frac{2 19}{5}

And the radius is:

r = \frac{2 19}{5}

x^{2} + y^{2} - 6 x + 10 y + 9 = 0

x^{2} + y^{2} + 12 y + 32 = 0

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

x^{2} - 6 x + 9 + y^{2} - 4 y + 4 = 16

x^{2} + y^{2} - 4 x + 6 y - 3 = 0

What is the radius 5x^2-20x+5y^2+30y-11=0 ?
The radius 5x^2-20x+5y^2+30y-11=0 is r=(2sqrt(19))/(sqrt(5))