What is the radius (x+1)^2+(y-2)^2=9 ?

The radius (x+1)^2+(y-2)^2=9 is r=3

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radius (x+1)^2+(y-2)^2=9

radius

(x + 1)^{2} + (y - 2)^{2} = 9

r = 3

Solution steps

(x + 1)^{2} + (y - 2)^{2} = 9

Rewrite

(x + 1)^{2} + (y - 2)^{2} = 9

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, 2), r = 3

And the radius is:

r = 3

x^{2} + (y - 1)^{2} = 1

x^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} - 2 y - 8 = 0

(x + 3)^{2} + (y - 3)^{2} = 8

(x - \frac{3}{2})^{2} + y^{2} = \frac{9}{4}