What is the radius (x-3)^2+(y-5)^2=24 ?

The radius (x-3)^2+(y-5)^2=24 is r=sqrt(24)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius (x-3)^2+(y-5)^2=24

radius

(x - 3)^{2} + (y - 5)^{2} = 24

r = 24

Solution steps

(x - 3)^{2} + (y - 5)^{2} = 24

Rewrite

(x - 3)^{2} + (y - 5)^{2} = 24

in the form of the standard circle equation

(x - 3)^{2} + (y - 5)^{2} = (24)^{2}

Therefore the circle properties are:

(a, b) = (3, 5), r = 24

And the radius is:

r = 24

x^{2} + y^{2} + 4 x - 6 y - 12 = 0

x^{2} - 8 x + y^{2} + 6 y = - 9

(x + 1)^{2} + (y - 5)^{2} = 5^{2}

x^{2} + y^{2} - 13 = 0

(x + \frac{7}{2})^{2} + (y - \frac{1}{2})^{2} = 5

What is the radius (x-3)^2+(y-5)^2=24 ?
The radius (x-3)^2+(y-5)^2=24 is r=sqrt(24)