What is the radius x^2+y^2-6x+5=0 ?

The radius x^2+y^2-6x+5=0 is r=2

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radius x^2+y^2-6x+5=0

radius

x^{2} + y^{2} - 6 x + 5 = 0

r = 2

Solution steps

x^{2} + y^{2} - 6 x + 5 = 0

Rewrite

x^{2} + y^{2} - 6 x + 5 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 2

And the radius is:

r = 2

2 x^{2} + 2 y^{2} - 9 x - 18 y - 80 = 0

5 x^{2} + 5 y^{2} + 10 x + 2 y + 3 = 0

x^{2} + y^{2} = 48

x^{2} + y^{2} - x + 6 y + 9 = 0

(x - 4)^{2} + (y + 12)^{2} = 1 7^{2}