What is the radius x^2+(y+4)^2=121 ?

The radius x^2+(y+4)^2=121 is r=11

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius x^2+(y+4)^2=121

radius

x^{2} + (y + 4)^{2} = 121

r = 11

Solution steps

x^{2} + (y + 4)^{2} = 121

Rewrite

x^{2} + (y + 4)^{2} = 121

in the form of the standard circle equation

(x - 0)^{2} + (y - (- 4))^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (0, - 4), r = 11

And the radius is:

r = 11

(x + 2)^{2} + (y + 4)^{2} = 4

(x + 2)^{2} + (y - 3)^{2} = 4

(x + 2)^{2} + (y - 3)^{2} = 9

2 x^{2} + 2 y^{2} + 44 x + 28 y = 52

x^{2} + y^{2} + 4 x + 2 y - 11 = 0