What is the radius x^2+y^2+8x+6y=0 ?

The radius x^2+y^2+8x+6y=0 is r=5

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radius x^2+y^2+8x+6y=0

radius

x^{2} + y^{2} + 8 x + 6 y = 0

r = 5

Solution steps

x^{2} + y^{2} + 8 x + 6 y = 0

Rewrite

x^{2} + y^{2} + 8 x + 6 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 3), r = 5

And the radius is:

r = 5

(x - \frac{1}{2})^{2} + (y - \frac{1}{2})^{2} = \frac{9}{4}

+ x^{2} + y^{2} - 4 x = 0

x^{2} - 6 x + 14 y - 567 + y^{2} = 0

x^{2} + y^{2} + 2 x - 4 y - 4 = 0

6 (x - 3)^{2} + 6 (y + 7)^{2} = 216