What is the radius (x-2.5)^2+(y-0.5)^2=14.5 ?

The radius (x-2.5)^2+(y-0.5)^2=14.5 is r=3.80788…

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radius (x-2.5)^2+(y-0.5)^2=14.5

radius

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

r = 3.80788 \dots

Solution steps

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

Rewrite

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

in the form of the standard circle equation

(x - 2.5)^{2} + (y - 0.5)^{2} = 3.80788 \dots^{2}

Therefore the circle properties are:

(a, b) = (2.5, 0.5), r = 3.80788 \dots

And the radius is:

r = 3.80788 \dots

(x - 5)^{2} + (y - 12)^{2} = 9

4 x^{2} + 4 y^{2} - 16 = 0

3 (x - 5)^{2} + 3 y^{2} = 27

x^{2} + y^{2} + 12 y = - 32

(x - 1)^{2} + (y + 3)^{2} - 9 = 0

What is the radius (x-2.5)^2+(y-0.5)^2=14.5 ?
The radius (x-2.5)^2+(y-0.5)^2=14.5 is r=3.80788…