What is the radius x^2+y^2-10x-10y=-1 ?

The radius x^2+y^2-10x-10y=-1 is r=7

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radius x^2+y^2-10x-10y=-1

radius

x^{2} + y^{2} - 10 x - 10 y = - 1

r = 7

Solution steps

x^{2} + y^{2} - 10 x - 10 y = - 1

Rewrite

x^{2} + y^{2} - 10 x - 10 y = - 1

in the form of the standard circle equation

(x - 5)^{2} + (y - 5)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (5, 5), r = 7

And the radius is:

r = 7

x^{2} + y^{2} - 4 x + 2 y + 4 = 0

x^{2} + y^{2} - 4 x + 16 y + 4 = 0

(x - 2)^{2} + (y + 3)^{2} = 16

(x - 1)^{2} + (y - 3)^{2} = 49

364 + 28 y + y^{2} + x^{2} = - 26 x