What is the radius (x-1)^2+(y+2)^2=16 ?

The radius (x-1)^2+(y+2)^2=16 is r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

radius (x-1)^2+(y+2)^2=16

radius

(x - 1)^{2} + (y + 2)^{2} = 16

r = 4

Solution steps

(x - 1)^{2} + (y + 2)^{2} = 16

Rewrite

(x - 1)^{2} + (y + 2)^{2} = 16

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 4

And the radius is:

r = 4

x^{2} + y^{2} + 6 x - 4 y + 12 = 0

(x - 2)^{2} + (y - (- 5))^{2} = 97

(x - 5)^{2} + y^{2} = 9

x^{2} - 4 x + 12 y + y^{2} + 14 = 0

x^{2} + y^{2} - 16 x - 4 = 0