What is the radius 3x^2-12x-18y+3y^2=0 ?

The radius 3x^2-12x-18y+3y^2=0 is r=sqrt(13)

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radius 3x^2-12x-18y+3y^2=0

radius

3 x^{2} - 12 x - 18 y + 3 y^{2} = 0

r = 13

Solution steps

3 x^{2} - 12 x - 18 y + 3 y^{2} = 0

Rewrite

3 x^{2} - 12 x - 18 y + 3 y^{2} = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - 3)^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (2, 3), r = 13

And the radius is:

r = 13

(x - 1)^{2} + (y + 4)^{2} = 9

x^{2} + y^{2} - 3 x + 4 y + 4 = 0

y^{2} = 4 - x^{2}

(x - 17)^{2} + (y + 5)^{2} = 144

3 x^{2} + 3 y^{2} + 2 x - 4 y - 1 = 0

What is the radius 3x^2-12x-18y+3y^2=0 ?
The radius 3x^2-12x-18y+3y^2=0 is r=sqrt(13)