What is the circumference 4x^2+4y^2-4x+2y-1=0 ?

The circumference 4x^2+4y^2-4x+2y-1=0 is C=(3pi)/2

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circumference 4x^2+4y^2-4x+2y-1=0

circumference

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0

C = \frac{3 π}{2}

Solution steps

C = 2 π r

Find the radius

Radius given

4 x^{2} + 4 y^{2} - 4 x + 2 y - 1 = 0 : r = \frac{3}{4}

C = 2 π \frac{3}{4}

Refine

C = \frac{3 π}{2}

(x - 1)^{2} + (y - 2)^{2} = 4

(x + 2)^{2} + (y - 3)^{2} = 16

x^{2} + y^{2} \leq + 16

(x + 6)^{2} + (y + 5)^{2} = 8

x^{2} + y^{2} - 4 x - 6 y - 12 = 0

What is the circumference 4x^2+4y^2-4x+2y-1=0 ?
The circumference 4x^2+4y^2-4x+2y-1=0 is C=(3pi)/2