What is the circumference (x+4)^2+(y+3)^2=18 ?

The circumference (x+4)^2+(y+3)^2=18 is C=6sqrt(2)pi

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circumference (x+4)^2+(y+3)^2=18

circumference

(x + 4)^{2} + (y + 3)^{2} = 18

C = 62 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 4)^{2} + (y + 3)^{2} = 18 : r = 18

C = 2 π 18

Refine

C = 62 π

(x + 4)^{2} + (y + 3)^{2} = 25

x^{2} + y^{2} = 4^{2}

6 x^{2} + 6 y^{2} + 6 x - 6 y - 6 = 0

(x - 3)^{2} + (y + 2)^{2} = 25

x^{2} + y^{2} = 100

What is the circumference (x+4)^2+(y+3)^2=18 ?
The circumference (x+4)^2+(y+3)^2=18 is C=6sqrt(2)pi