What is the circumference (x-3)^2+(y+2)^2=25 ?

The circumference (x-3)^2+(y+2)^2=25 is C=10pi

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circumference (x-3)^2+(y+2)^2=25

circumference

(x - 3)^{2} + (y + 2)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 3)^{2} + (y + 2)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} = 100

x^{2} + y^{2} + 4 x - 6 y - 12 = 0

3 x^{2} + 3 y^{2} + 6 x - 4 y = 0

(x + 3)^{2} + (y - 2)^{2} = \frac{9}{4}

(x - 2)^{2} + (y - 9)^{2} = 1 6^{2}

What is the circumference (x-3)^2+(y+2)^2=25 ?
The circumference (x-3)^2+(y+2)^2=25 is C=10pi