What is the circumference x^2+y^2+4x-6y-12=0 ?

The circumference x^2+y^2+4x-6y-12=0 is C=10pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference x^2+y^2+4x-6y-12=0

circumference

x^{2} + y^{2} + 4 x - 6 y - 12 = 0

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x - 6 y - 12 = 0 : r = 5

C = 2 π 5

Refine

C = 10 π

3 x^{2} + 3 y^{2} + 6 x - 4 y = 0

(x + 3)^{2} + (y - 2)^{2} = \frac{9}{4}

(x - 2)^{2} + (y - 9)^{2} = 1 6^{2}

x^{2} + y^{2} + 6 x - 4 y - 51 = 0

x^{2} + y^{2} - 4 x - 6 y + 9 = 0

What is the circumference x^2+y^2+4x-6y-12=0 ?
The circumference x^2+y^2+4x-6y-12=0 is C=10pi