What is the circumference (x-1)^2+(y-6)^2=25 ?

The circumference (x-1)^2+(y-6)^2=25 is C=10pi

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circumference (x-1)^2+(y-6)^2=25

circumference

(x - 1)^{2} + (y - 6)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 1)^{2} + (y - 6)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} + 8 x - 2 y - 19 = 0

(x - 2)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

x^{2} + y^{2} = 2.5

4 x - x^{2} - y^{2} - 6 y - 2 \geq 0

What is the circumference (x-1)^2+(y-6)^2=25 ?
The circumference (x-1)^2+(y-6)^2=25 is C=10pi