What is the circumference (x-4)^2+(y+1)^2=41 ?

The circumference (x-4)^2+(y+1)^2=41 is C=2sqrt(41)pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

circumference (x-4)^2+(y+1)^2=41

circumference

(x - 4)^{2} + (y + 1)^{2} = 41

C = 241 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 4)^{2} + (y + 1)^{2} = 41 : r = 41

C = 241 π

2 x^{2} + 2 y^{2} - 24 x + 28 y + 120 = 0

x^{2} + y^{2} = 17

x^{2} + y^{2} = 13

(x - 0)^{2} + (y - 0)^{2} = \frac{52}{4}

x^{2} + y^{2} = 10

What is the circumference (x-4)^2+(y+1)^2=41 ?
The circumference (x-4)^2+(y+1)^2=41 is C=2sqrt(41)pi