What is the circumference x^2+y^2+4x-8y=0 ?

The circumference x^2+y^2+4x-8y=0 is C=4sqrt(5)pi

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circumference x^2+y^2+4x-8y=0

circumference

x^{2} + y^{2} + 4 x - 8 y = 0

C = 45 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 4 x - 8 y = 0 : r = 25

C = 2 π 25

Refine

C = 45 π

2 x^{2} + 2 y^{2} - 8 x - 12 y + 8 = 0

(x - 3)^{2} + (y + 4)^{2} = 8

x^{2} + y^{2} - 6 y = 16

2 x^{2} + 2 y^{2} + 10 x - 6 y + 3 = 0

4 x^{2} + 4 y^{2} + 12 x - 4 y - 88 = 0

What is the circumference x^2+y^2+4x-8y=0 ?
The circumference x^2+y^2+4x-8y=0 is C=4sqrt(5)pi